GCSE Science Alongside and alternation circuits answers

 18 June 02:49   

    ::V₁ = 2V

    ::V₂ = 3V

    ::V₁ = 3V

    ::V₂ = 3V

    ::=5/1

    ::= 5Ω

    So R₂ = 3Ω

    Yes it does.

    Ideally it should not create any difference. The accuracy of the lit ball should abide the same. (In practise the ball will apparently dim a tiny bit because of the centralized attrition of the battery, but thats added avant-garde than this course)

    It absolutely would.

    R₁ + R₂ = 1 + 1 = 2 Ω

    Let the Voltage be V.

    From Ohms Law

    :current I₁ = V/2 A

    :current I₂ = V/3 A

    So the absolute Accepted I = V/2+V/3

    :::= V(1/2 +1/3)

    :::= V (5/6)

    Now we Administer Ohms Law to the ambit afresh alone this time using the absolute accepted so that we understand what the totla attrition is-

    R = V/I

    : = V/

    : = 1/(5/6) We abolish the Vs

    : = 6/5 To bisect by a fraction, about-face it upside down and multiply

    Rather than traveling through the accomplished proceedure for Q8 afresh we agenda that -

    1/R = 1/R₁ + 1/R₂ + 1/R₃

    : = 1/2 + 1/2 + 1/3

    : = 4/3

    So R = 3/4 Ω