Algebra I - A Bombastic Access Factoring

 10 August 02:07   

    A agency of a amount is any two numbers that can be assorted calm to create the amount we are factoring. An archetype a agency of the amount 16 is (8 and 2) because 8

    Before we alpha factoring we charge to apprentice a concordance term: bisect evenly. Bisect analogously agency that if you bisect two numbers calm there isnt a butt or there is a butt of aught (how anytime you wish to say it). 2 divides analogously into 4 because 2 disconnected by 4 is 2. 3 does not bisect analogously into 14 because 3 disconnected by 14 is 4 with a butt of 2.

    To agency we haveto first attending for accessible factors. Accessible factors are any amount that ability be a factor. Already we accept a accessible agency then we bisect that amount into the amount we are factoring. If they bisect analogously then we accept a factor! The agency is the accessible agency we begin and the aftereffect of the analysis problem. Actuality is an example. Lets say the amount we are factoring is 20. 2 is the accessible factor. 20 / 2 = 10. They bisect analogously which agency we accept a factor. The factors are 2 (the accessible factor), and 10 (the aftereffect of the analysis problem). Now that we accept a agency we alpha over with a new accessible agency and acquisition all of the factors.

    The accessible factors for any amount are every amount amid one and itself. For archetype the factors for 12 are: 1,2,3,4,5,6,7,8,9,10,11, and 12. Try every agency in adjustment starting at one.

    Lets agency some numbers

    Factor 12

    First acquisition all the accessible factors

    The accessible factors are 1,2,3,4,5,6,7,8,9,10,11, and 12

    next we will try them one by one

    12/1 = 12 (1 and 12 are factors)

    12/2 = 6 (2 and 6 are factors)

    12/3 = 4 (3 and 4 are factors)

    12/4 = 3 (we already accept the factors 3 and 4)

    Once we get a agency we already accept then we understand we accept all the factors.

    So the factors for 12 are (1 and 12), (2 and 6), and (3 and 4)

    ----

    Factor 54

    First acquisition all the accessible factors

    The accessible factors are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, and 54

    Do not anguish this is not as abundant plan as it seems!

    54/1 = 54 (1 and 54 are factors)

    54/2 = 27 (2 and 27 are factors)

    54/3 = 18 (3 and 18 are factors)

    54/4 = 13r2 (4 is not a factor)

    54/5 = 10r4 (5 is not a factor)

    54/6 = 9 (6 and 9 are factors)

    54/7 = 7r5 (7 is not a factor)

    54/8 = 6r6 (8 is not a factor)

    54/9 = 6 (we already accept the factors 9 and 6)

    See that was easy.

    So the factors for 54 are (1 and 54), (2 and 27), (3 and 18), and (6 and 9)