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You are here: Articles >Reference & Education > Book

Algebra Added Addition Answers to Backer Contest 1

 10 June 16:07   

    1. What are 4^3, 3^4, 1^, ^1?

    Answers:

    ::a. 4^3 = 4 cdot 4 cdot 4 = 64

    ::b. 3^4 = 3 cdot 3 cdot 3 cdot 3 = 81

    ::c. 1^ = 1 cdot 1 cdot 1 cdot .,.,.,. cdot 1 cdot 1 cdot 1 = 1

    ::d. ^1 = 250

    2. Address these numbers as admiral of 2: 128, 8, 1024

    Answers:

    ::a. 128 = 2^7

    ::b. 8 = 2^3

    ::c. 1024 = 2^

    3. What is (2^3)

    Answer:

    :::(2^3) cdot (2^2) = 2^ = 2^5 = 32

    4. What is (2^6)/(2^2)?

    Answer:

    :::(2^6)/(2^2) = 2^ = 2^4 = 16

    5. Harder: Why does 3^0=1? (clue: anticipate about /, for example)

    Answer:

    :::/ = 3^ = 3^0

    ::: 3^2 = 3 cdot 3 = 9

    ::: / = 9/9 = 1

    ::From the first and third equations above, we can see that:

    ::: / = 3^0 = 1

    ::The backer doesnt accept to be 2. The backer can be any absolute amount and the aforementioned argumentation would work. It was mentioned in the first affiliate that a amount aloft to the 0 ability equals 1; i. e.,    

    
a^0 = 1 .


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