Programming LearnByExample Octave

 15 July 06:23   Agnate to Matlab.

    Suppose you wish to solve

    3x + 6y + 8z = 3

    78x + 4y + 2z = 0

    77x + 32y + 14z = -4

     octave> a = [3 6 8 ; 78 4 2; 77 32 14]

     a =

     3 6 8

     78 4 2

     77 32 14

     octave> b = [3 0 -4]

     b =

     3

     0

     -4

    the abettor transposes a matrix/vector. Defining b = [3;0;-4] is the aforementioned result.

     octave> a

     ans =

     3 78 77

     6 4 32

     8 2 14

    3x + 6y + 8z = 3

    78x + 4y + 2z = 0

    77x + 32y + 14z = -4

     octave> d = [3 6 8 3; 78 4 2 0 ; 77 32 14 -4]

     d =

     3 6 8 3

     78 4 2 0

     77 32 14 -4

     octave> rref(d)

     ans =

     1.00000 0.00000 0.00000 0.00472

     0.00000 1.00000 0.00000 -0.44600

     0.00000 0.00000 1.00000 0.70773

    With the solution

     x = 0.00472

     y = -0.44600

     z = 0.70773

     octave> c= a

     c =

     0.0047249

     -0.4460007

     0.7077287

     octave> a ans =

     3.00000

     0.00000

     -4.00000

    As you can see, b = a